fix: 正确的在 Darwin 上替换 zrc source 的实现

init_priv.sh

@@ -127,21 +127,6 @@ configure_vim() {
     fi
 }
 
-replace_zsh_source() {
-    local zshrc="$HOME/.zshrc"
-    local old_source="\$ZSH/oh-my-zsh.sh"
-    local new_source="~/.oh-my-zsh/custom/00-init.zsh"
-
-    # 使用 sed 进行替换，注意 macOS 和 Linux 的 sed 语法稍有不同
-    if [ "$(uname)" = "Darwin" ]; then
-        # macOS 使用的是 BSD sed，需要给 -i 选项传递一个空字符串作为扩展名
-        sed -i '' "s|${old_source}|${new_source}|g" "$zshrc"
-    else
-        # Linux 使用的是 GNU sed
-        sed -i "s|${old_source}|${new_source}|g" "$zshrc"
-    fi
-}
-
 configure_zsh() {
     [ -f ~/.zshrc ] && return
 
@@ -158,7 +143,20 @@ configure_zsh() {
         pkg_install autojump
 
         if ! grep -Fxq "source ~/.oh-my-zsh/custom/00-init.zsh" ~/.zshrc; then
-            replace_zsh_source
+            local zshrc="$HOME/.zshrc"
+            local search_line="source \$ZSH/oh-my-zsh.sh"
+            local add_line="source ~/.oh-my-zsh/custom/00-init.zsh"
+
+            if [ "$(uname)" = "Darwin" ]; then
+                # macOS
+                awk -v search="$search_line" -v add="$add_line" '{
+                    if (index($0, search) > 0) print add
+                    print $0
+                }' "$zshrc" > ~/.zshrc.temp && mv ~/.zshrc.temp "$zshrc"
+            else
+                # Linux
+                sed -i "/${search_line}/i ${add_line}" "$zshrc"
+            fi
         fi
 
         cp $scriptdir/files/zsh/.zsh_user           ~/.zsh_user